Message-ID: <CAHOWgNXo+Tz_0KfGqY9R95NBDEuk_PTCGvW-S4n00xVJmG+DFQ@mail.gmail.com>
Date: 2015-05-15T17:05:53Z
From: Kai Mx
Subject: print dataframe names in loop
In-Reply-To: <CA+8X3fXUwjVTAJ3fUOHB_5VA1gsv2XZJBrugHbwa6bViiP5C2A@mail.gmail.com>
thanks, that would work, but isn't there a maybe more elegant way to
"extract" the name from the df variable within the current for (df in
list()) loop?
Best,
Kai
On Fri, May 15, 2015 at 2:20 PM, Jim Lemon <drjimlemon at gmail.com> wrote:
> Hi Kai,
> One way is to name the components of your list with the names of the
> data frames:
>
> df1<-data.frame(a=1:3)
> df2<-data.frame(a=4:6)
> df3<-data.frame(a=7:9)
> dflist<-list(df1,df2,df3)
> names(dflist)<-c("df1","df2","df3")
> for(i in 1:length(dflist)) cat(names(dflist)[i],"\n")
> df1
> df2
> df3
>
> Jim
>
>
> On Fri, May 15, 2015 at 10:05 PM, Kai Mx <govokai at gmail.com> wrote:
> > Hi everybody,
> >
> > I just can't figure this out:
> >
> > I have a loop trough several dataframes such as
> >
> > for (df in list(df1, df2, df3, ...)) {
> > ..some functions with df..
> > }
> >
> > now I want to print out the current dataframes name (ie the list items
> > name) with the cat command before the actual functions to have better
> > orientation in the output.
> > However, I haven't been successful with different variations of
> deparse(),
> > substitute(), (cat(substitute(df)) gives me 'df' for the whole loop).
> >
> > Could somebody please enlighten me?
> >
> > Thanks so much!
> >
> > Best,
> >
> > Kai
> >
> > [[alternative HTML version deleted]]
> >
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