Plotting contour & filled.contour in one graph

GG

Yes, gladly.  It is an idealized example of the following data 
situation:  There are two control or "independent variables."  They are 
represented here as x and y, on the horizontal and vertical axes 
respectively.  There are two different responses or "dependent" 
variables plotted as different types of contours.  The filled contours 
show response z.  The heavy lines show response zz.

Thus such a plot displays two different responses from a two-dimensional 
range of conditions.  As an example, in fishery biology, x might be the 
age at which fish are first subject to capture, y might be the fishing 
mortality rate (intensity) applied, z might be the resulting yield per 
fish, and zz might be the resulting spawning per fish.  There is usually 
a trade-off between yield and spawning potential, and such a graph (if 
done with real data) allows one to look at that trade-off. 

The OP seemed to be seeking a way of contouring two responses against 
two independent variables, and that's what this graph does.

Is that clearer?  Would the graph would be better if I used real data?

MHP



Gabor Grothendieck wrote on 2/12/2006 11:31 AM:

Could you walk us through, in detail, what that graph is showing?


On 2/12/06, Michael Prager <Mike.Prager at noaa.gov> wrote:
 

Besides the answers you already have, you might look at my "4D" graph
example (with code) on the R Graphics Gallery:

http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=90

I think it does exactly what you are asking, and therefore it might fit
your needs with only slight code modification.

Mike Prager


Abd Rahman Kassim wrote on 2/12/2006 11:12 PM:
   

Dear All,

I have a question on overlaying a filled.contour (e.g. on soil properties data) and contour (by elevation) in one graph. Both have the same z matrix dimension. I'm able to overlay both graph, but the plots dimension did not overlap well on the same plots. How can I have both filled.contour and contour on the same graph? The commands that I have written are as follows:

filled.contour(0:15,0:10,t(matrix(Total.C,nrow=11,ncol=16)))
contour(0:15,0:10,as.matrix(elev),add=T)

Thanks for anay assistance.

Regards.


Abd Rahman Kassim
Forest Research Institute Malaysia
Kepong 52109
Selangor, MALAYSIA

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--
Michael H. Prager, Ph.D.
Population Dynamics Team
NOAA Center for Coastal Habitat and Fisheries Research
NMFS Southeast Fisheries Science Center
Beaufort, North Carolina  28516  USA
http://shrimp.ccfhrb.noaa.gov/~mprager/