Searching for antilog function

Consider: 

 > exp(log(1:11))
 [1]  1  2  3  4  5  6  7  8  9 10 11
 > 2^log(1:11, 2)
 [1]  1  2  3  4  5  6  7  8  9 10 11
 > 2^logb(1:11, 2)
 [1]  1  2  3  4  5  6  7  8  9 10 11
 > 10^log10(1:11)
 [1]  1  2  3  4  5  6  7  8  9 10 11
 > 2^log2(1:11)
 [1]  1  2  3  4  5  6  7  8  9 10 11

      Does this answer the question? 

      hope this helps. spencer graves

Searching for antilog function

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