lm with an arbitrary number of terms
The following might work:
mdl <- paste("y~", paste(names(data.frame), collapse="+"))
lm(mdl, ...)
If y = "y" is a column of your data.frame, you can delete it be
selecting "names(data.frame)[!is.element(y, names(data.frame)]"
Can you solve the problem from here?
Best Wishes,
Spencer Graves
Richard Nixon wrote:
Hello folks,
Any ideas how to do this?
data.frame is a data frame with column names "x1",...,"xn"
y is a response variable of length dim(data.frame)[1]
I want to write a function
function(y, data.frame){
lm(y~x1+...+xn)
}
This would be easy if n was always the same.
If n is arbitrary how could I feed the x1+...+xn terms into lm(response~terms)?
Thanks
Richard
--
Dr. Richard Nixon
MRC Biostatistics Unit, Cambridge, UK
http://www.mrc-bsu.cam.ac.uk/personal/richard
Tel: +44 (0)1223 330382, Fax: +44 (0)1223 33038
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