Message-ID: <CAAxdm-6DVG7o4kvXp9aMZxsS0gB2uprg0Zc5PvynPgQPLA+3ZQ@mail.gmail.com>
Date: 2012-05-08T00:50:17Z
From: jim holtman
Subject: Matrix "BYTES" size
In-Reply-To: <CAJ26pbLjA1pS8JADheaXg1OXny05iB5ybk4-y_jyYMyV5M3NCw@mail.gmail.com>
If all you want are binary 0/1, then look at the 'bit' package which
will let you create a vector of bits. Even for your matrix, you will
need almost 1GB of memory to store a copy.
On Mon, May 7, 2012 at 5:23 PM, Lucas <lpchaparrovio at gmail.com> wrote:
> Dear R people.
> I? facing a big problem.
> I need to create a matrix with 10.000 columns and 750.000 rows.
> matrix<- as.data.frame(matrix(data=0L, nrow=750000, ncol=10000)
> as you can see, the data frame has huge dimesions. I was able to find out
> about thr "L" in data, this way I? telling that my data is "integer"
> class. By doing this
> object.size(matrix) tells me that this is half of the matrix when I don?
> define as integer (L)
> The data that I?l be filling with my matrix will be 0 and 1, nothing else,
> so I could use less bytes.
> so, my cuestion is, How can I create the same matrix but using even less
> bytes?
>
> I?l appreciate if you can help me.
>
> Thank you.
> Lucas
>
> ? ? ? ?[[alternative HTML version deleted]]
>
>
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--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.