Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 11/6/13 9:19 AM, "Sashikanth Chandrasekaran"
<sashikanth.chandrasekaran at gmail.com> wrote:
>I am not trying to fit a horizontal line at every unique value of y. I am
>trying fit the y values with as few horizontal lines by trading off the
>number of horizontal lines with the error. The actual problem I am trying
>to solve is to smooth data in a time series. Here is a realistic example
>of
>y
>
>y=c(134.45,141.82,143.81,141.81,145,141.61,143.72,145.71,200,175,140,200,1
>48.77,71.64,111.57,118.15,119.15,112.8,111.64,111.64,157.26,143.8,40.19,64
>.99,64.99,129.98,64.99,65,64.98,64.99)
>
>An example fit for y using multiple horizontal lines (may not be the best
>fit in terms of squared error or another error metric, but I have included
>the y value for concreteness)
>
>1. A horizontal line at approximately y=140 (to fit the first 13 values -
>134.45 to 148.77)
>2. A horizontal line at approximately y=110 (to fit the next 7 values -
>71.64 to 111.64)
>3. A horizontal line at approximately y=150 (to fit the next 2 values -
>157.26 to 143.8)
>4. A horizontal line at approximately y=65 (to fit the last 8 values -
>40.19 to 64.99)
>-sashi.
>
> [[alternative HTML version deleted]]
>
>______________________________________________
>R-help at r-project.org mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide
>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.