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Message-ID: <1392309402.15726.YahooMailNeo@web142605.mail.bf1.yahoo.com>
Date: 2014-02-13T16:36:42Z
From: arun
Subject: plyr: colvar value corresponding to max Date
In-Reply-To: <CAHgH9_Eo3TSxhq86uruW_YnBDMkpRuWEsbhkJMwiJ1++qDvbRg@mail.gmail.com>

Hi,
Try ?which.max() # unique values for the combination.

?ddply(data,.(state),summarize,max_date=value[which.max(date)])[,2]
#or
?ddply(data,.(state),summarize,max_date=value[date == max(date)])[,2]


A.K.


On Thursday, February 13, 2014 11:15 AM, Dan Murphy <chiefmurphy at gmail.com> wrote:
I can do this in multiple steps with summarise, joins, etc., but can't
help thinking it can be accomplished in one plyr call.

Here's a small example:

> require(plyr)
> require(lubridate)
> data <- data.frame(
+?  date = rep(as.Date(ymd(20140101 + (0:3) * 100)), 2),
+?  state = rep(c("A", "B"), each = 4),
+?  value = rnorm(8))

What I want is clearly

> data[c(4, 8), "value"]
[1] -1.007111 -1.527541

Here are my multiple steps:

> statemaxval <- ddply(data, "state", summarise, max_date = max(date))
> rslt <- join(data, statemaxval, by = "state")
> rslt <- subset(rslt, date == max_date)
> rslt <- rslt[!duplicated(rslt), ]
> rslt$value
[1] -1.007111 -1.527541

Is there a one-step way to accomplish this?
Something like
ddply(data, "state", summarise, "GiveMeTheValueCorrespondingToMaxDateByState!!")

Or is that only possible if there is only one unique value for a given
combination of state and max(date)?

Thanks,
Dan

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