Counting NA?
Surely not the best method: length(which(is.na(data$S2)==TRUE))
On Wednesday 23 October 2002 08:48, Matej Cepl wrote:
Hi,
how to do quickly equivalent of the following?
counter = 0
for(i in 1:length(data$S2)) {
if(!is.na(data$S2[i])) {
counter = counter + 1
}
}
I have imagined something like length(x,na.rm=TRUE).
How can I get values usually taken from tables like z-score,
values of t distribution etc.? I could not find them among
values mentioned in info file.
Thanks,
Matej
David Wartel -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._