Populate a matrix
One more version: somewhere in the middle of the explicitness scale, matrix(rep(y, times = length(x)), nrow=length(y)) On Wed, Oct 5, 2011 at 12:17 PM, R. Michael Weylandt
<michael.weylandt at gmail.com> wrote:
matrix(rep(y, each=length(x)), nrow=length(y), byrow=TRUE) or less explicitly ?matrix(y, nrow=length(y),ncol=length(x)) Michael On Wed, Oct 5, 2011 at 12:11 PM, ?<fernando.cabrera at nordea.com> wrote:
Hi guys I have vectors x <- c(1,2,3,4) and y <- c(4,3,9) and would like to generate a matrix which has 3 rows (length(y)) and 4 columns (length(x)), and each row is the corresponding y element repeated length(x) times. 4,4,4,4 3,3,3,3 9,9,9,9 Thanks. Fernando ?lvarez
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