Plotting own function
You need to use 'ifelse' in this case since it will handle a vector
and 'if' is only for single values:
func <- function(x) {
y <- exp(-0.5*((x-63.9)/23.2)^2)
ifelse(x > 63.9, 2 - y, y)
}
x = seq(-10,150,length=500)
y <- func(x)
plot(x,y,type="l",lwd=2,col="red")
On Tue, Dec 7, 2010 at 6:57 AM, Tobias Schultze <webmaster at tubo-world.de> wrote:
Hello,
I have a simple question but didn't find a solution.
How do I plot a custom function.
I have defined this function
func <- function(x) {
? ? ? ?y <- exp(-0.5*((x-63.9)/23.2)^2)
? ? ? ?if(x > 63.9)
? ? ? ? ? ? ? ?return(2 - y)
? ? ? ?else {
? ? ? ? ? ? ? ?return(y)
? ? ? ?}
}
and want to plot it in a specified range like
x = seq(-10,150,length=500)
y <- func(x)
plot(x,y,type="l",lwd=2,col="red")
But it doesn't work because it expects a vector but I need to compare the
scalar x.
How do I do it correctly?
Thanks a lot
Tobias
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