Reformatting dates using chron
Prof Brian D Ripley writes:
On Fri, 12 Jan 2001, Andrew Criswell wrote:
Hello All:
I am trying to generate a sequence of dates using library(chron). Using the following code, I got most of what I want,
dts <- seq.dates("01/02/1998", "01/10/2001", by="day")
dts <- dts[!is.weekend(dts)]
a sequence of weekdays only (no weekend dates), with first observation appearing as 01/02/98 and the last 01/10/01. But I would like it to appear as 1998/01/02 to 2001/01/10.
Is there some way to change the order of the output and allow "year" to appear with four digits and slash signs between year, month and day?
(I am using R 1.2.0 on a Windows 2000 platform.)
That's how they print.
attr(dts, "format") <- "y/m/d"
gives
dts[1]
[1] 98/01/02
I can't get `year' to work in there, so try
format(as.POSIXct(dts), "%Y/%m/%d")
which does work and is very flexible.
Using the standard formatting tools from chron, you can do e.g. format(dts) <- "year month day" which will give R> dts [1] 1998 January 02 1998 January 03 1998 January 04 1998 January 05 etc, but you cannot get a full year immediately followed by a non space separtor. You could write a *function* which produces the format you want ... but as Brian correctly points out, using the new date/time classes in R 1.2 is much more convenient. -k -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._