Hi,
Forgot the last part.
colnames(dat3New)<-c("name","slope","percentage")
?dat3New
???????????????????????????????? name?????????? slope??? percentage
1????????? Budlamp-Woodcutter Complex 15 to 60% slope??? (60/25/15)
2????????? Budlamp-Woodcutter Complex 15 to 60% slope??? (60/25/15)
3 Terrarossa-Blacktail-Pyeatt Complex? 1 to 40% slope (40/35/15/10)
4 Terrarossa-Blacktail-Pyeatt Complex? 1 to 40% slope (40/35/15/10)
A.K.
----- Original Message -----
From: Sapana Lohani <lohani.sapana at ymail.com>
To: "r-help at r-project.org" <r-help at r-project.org>
Cc:
Sent: Thursday, August 16, 2012 2:41 PM
Subject: [R] How to extract from a column in a table?
Hi,
I have a table in which one column has the name of the objects as shown below.
Name
Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15)
Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15)
Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10)
Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10)
How can I split the single column into three columns like name (Budlamp-Woodcutter Complex), slope (15 to 60% slope) and percentage (60/25/15)
thanks
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