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Distinguishing variables from functions with the same name

G'day Stavros,

On Fri, 13 Feb 2009 11:11:28 -0500
Stavros Macrakis <macrakis at alum.mit.edu> wrote:

            
I guess the answer to this question is more often than not in the source. :)
On my machine:

berwin at berwin-nus1:/opt/src/R-devel-src/src/library$ find . -name "*.R" -type f | xargs grep "get(" \
./tools/R/QC.R:            al <- get(al, envir = code_env, mode = "list")
./tools/R/QC.R:            al <- get(al, envir = ns_env, mode = "list")
./tools/R/QC.R:                al <- get(al, envir = data_env, mode = "list")
./utils/R/Sweave.R:        syntax <- get(syntax, mode="list")
./utils/R/Sweave.R:        syntax <- get(sname, mode = "list")
./utils/R/Sweave.R:        s <- get(sname, mode="list")
./utils/R/str.R:        str(get(nam, envir = E, mode = M),
./stats/R/model.tables.R:       tables[[i]] <- tapply(data, model[model.cols[[i]]], get(fun))
./stats/R/models.R:        ##     get(contr.funs[1 + isOF[nn]])(nlevels(data[[nn]]))
./base/R/get.R:    .Internal(get(x, envir, mode, inherits))
./base/R/get.R:     .Internal(mget(x, envir, mode, ifnotfound, inherits))
./base/R/match.fun.R:        FUN <- get(as.character(FUN), mode =
"any", envir = envir)


The first few hits seem to indicate examples where it is necessary 
to look specifically for a list.

Cheers,

	Berwin