Stacking of vectors to form a column vector

Thu, Apr 30, 2015 9:32 AM

Hi,

Given that a data frame is a list:

  unlist(mydata[, 1:3])

For example:

[1] TRUE


Also, note that the returned result in both cases above retains names:

Sepal.Length1   Sepal.Length2   Sepal.Length3   Sepal.Length4 
            5.1             4.9             4.7             4.6 
  Sepal.Length5   Sepal.Length6   Sepal.Length7   Sepal.Length8 
            5.0             5.4             4.6             5.0 
  Sepal.Length9  Sepal.Length10  Sepal.Length11  Sepal.Length12 
            4.4             4.9             5.4             4.8 
...

You can just get the plain vector by using:

[1] 5.1 4.9 4.7 4.6 5.0 5.4 4.6 5.0 4.4 4.9 5.4 4.8 4.8 4.3 5.8 5.7
 [17] 5.4 5.1 5.7 5.1 5.4 5.1 4.6 5.1 4.8 5.0 5.0 5.2 5.2 4.7 4.8 5.4
 [33] 5.2 5.5 4.9 5.0 5.5 4.9 4.4 5.1 5.0 4.5 4.4 5.0 5.1 4.8 5.1 4.6
 [49] 5.3 5.0 7.0 6.4 6.9 5.5 6.5 5.7 6.3 4.9 6.6 5.2 5.0 5.9 6.0 6.1
...


As Bert notes, the indices would need to be adjusted for the actual data frame in question.

Regards,

Marc

On Apr 30, 2015, at 10:52 AM, Bert Gunter <gunter.berton at gene.com> wrote:

... and if this is what is wanted, somewhat cleaner and more
generalizable for programming would be:

do.call(c, mydata[,1:3])

## where the column indices might have to be adjusted to get the
desired columns.

Cheers,

Bert

Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374

"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
Clifford Stoll




On Wed, Apr 29, 2015 at 11:51 PM, Jim Lemon <drjimlemon at gmail.com> wrote:

Hi Olufemi,
I sounds like you have a data frame (let's call it "mydata") with at
least three elements (columns). You may be trying to use c() in this
way:

y1to3<-c(y1,y2,y3)

in which case it won't work. However:

y1to3<-c(mydata$y1,mydata$y2,mydata$y3)

might do what you want, substituting whatever the name of your data
frame is for "mydata".

Jim


On Thu, Apr 30, 2015 at 1:20 PM, Jeff Newmiller
<jdnewmil at dcn.davis.ca.us> wrote:

I am sure you can use c() because columns may be vectors even though vectors are not columns, but you really need to follow the posting guide and provide a reproducible example for us to show you how. You might find [1] helpful, in particular as it describes the use of the dput function to give us a few rows of your data.

[1] http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
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On April 29, 2015 7:48:24 PM PDT, Olufemi Bolarinwa <dafemlions at yahoo.co.uk> wrote:

Thank you Jeff for your response.
My y1, y2, y3 are actually 3 columns in the data so I cannot use the
c() function to concatenate them. I am confusing the "columns" with
vectors. I actually meant columns.
Any help will be much appreciated
Olufemi



On Wednesday, 29 April 2015, 22:31, Jeff Newmiller
<jdnewmil at dcn.davis.CA.us> wrote:


Vectors are not "columns" or "rows". Use the c() function to
concatenate vectors.
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Go...
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rocks...1k
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On April 29, 2015 6:56:46 PM PDT, Olufemi Bolarinwa
<dafemlions at yahoo.co.uk> wrote:

Hello,I am estimating a system of nonlinear equation where I need to
stack my vector of y. I have data of about 6000units. I tried using

the

rbind but instead of having a vector of 1 by 18000, it is giving me a

by 6000 so that my matrix multiplication is non-conformable. The stack
command requires an identifier but in this case, I do not have a

unique

identifier.
I would like to stack the the first 6000 units of y1 on the 2nd 6000
units of y2 and 6000 units of y3.
Any help will be greatly appreciated.
ThanksOlufemi

Stacking of vectors to form a column vector

Thread (10 messages)