lapply and for

Given a list as such:

milista

$"1":
[1] 23 25 11

$"2":
[1] 34  2

$"3":
[1]   12    1    0 1050    2

What's faster:

a <- NULL
for (i in names(milista)){

+ a <- c(a,(mean(milista[[i]])))
+ }

or

a <- lapply(milista,mean)


?

(I understand that the second option
is nicer and more compact, but is it
faster?).

Thanks

Agus

Dr. Agustin Lobo
Instituto de Ciencias de la Tierra (CSIC)
Lluis Sole Sabaris s/n
08028 Barcelona SPAIN
tel 34 93409 5410
fax 34 93411 0012
alobo at ija.csic.es


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