a more elegant approach to getting the majority level

Hi, I have a factor and I would like to find the most frequent level.

I think my current approach is a bit long winded and I was wondering if
there was a more elegant way to do it:

x <- factor(sample(1:0, 5,replace=TRUE))

levels(x)[ which( as.logical((table(x) == max(table(x)))) == TRUE ) ]
(== TRUE) can ALWAYS be omitted, see also:
  library(fortunes)
  fortune("TRUE")

x == max(x) should be replaced by which.max(x)

as.logical() is superfluous

Hence we get:
   names(which.max(table(x)))

Uwe Ligges
(The length of x will always be an odd number, so I wont get a tie in
max())

Thanks,

-------------------------------------------------------------------
Rajarshi Guha <rxg218 at psu.edu> <http://jijo.cjb.net>
GPG Fingerprint: 0CCA 8EE2 2EEB 25E2 AB04 06F7 1BB9 E634 9B87 56EE
-------------------------------------------------------------------
Alcohol, an alternative to your self
- 'Alcohol' by the Bare Naked Ladies

______________________________________________
R-help at stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html

a more elegant approach to getting the majority level

Thread (4 messages)