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Counting occurrences in a moving window

On Thu, Jun 2, 2011 at 11:41 AM, mdvaan <mathijsdevaan at gmail.com> wrote:
Try this:
+ sum(DF$B < DF$B[i] & DF$B >= DF$B[i]-3 & DF$A[i] == DF$A))
A    B C
1  8025 1995 0
2  8026 1995 0
3  8029 1995 0
4  8026 1996 1
5  8025 1997 1
6  8026 1997 2
7  8025 1997 1
8  8027 1997 0
9  8026 1999 2
10 8027 1999 2
11 8028 1995 0
12 8029 1998 1
13 8025 1997 1
14 8027 1997 0
15 8026 1999 2
16 8027 1999 2
17 8028 1995 0
18 8029 1998 1