calculate time from dates
Hello, The functions in stackoverflow need a date 'format' argument. # Functions from # http://stackoverflow.com/questions/1995933/number-of-months-between-two-dates # with a 'format' argument added # # turn a date into a 'monthnumber' relative to an origin monnb <- function(d, format = "%Y-%m-%d") { lt <- as.POSIXlt(as.Date(d, origin="1900-01-01", format = format)) lt$year*12 + lt$mon } # compute a month difference as a difference between two monnb's mondf <- function(d1, d2, format = "%Y-%m-%d") { monnb(d2, format = format) - monnb(d1, format = format) } dat1 <- read.table(text = " ID date 1 4/12/2008 1 4/13/2008 1 5/11/2008 2 3/21/2009 2 4/22/2009 2 8/05/2009 ", header = TRUE) dat2 <- data.frame(ID = dat1$ID, month = mondf("01/01/2008", dat1$date, format = "%m/%d/%Y") + 1) # Now keep just the last one if month diffs are equal result <- with(dat2, aggregate(month, list(ID, month), FUN = tail, 1))[1:2] names(result) <- names(dat2) result Hope this helps, Rui Barradas Em 11-07-2013 11:03, andrija djurovic escreveu:
Hi. See http://stackoverflow.com/questions/1995933/number-of-months-between-two-dates Andrija On Thu, Jul 11, 2013 at 11:56 AM, Gallon Li <gallon.li at gmail.com> wrote:
My data are from 2008 to 2010, with repeated measures for same subjects. I
wish to compute number of months since january 2008.
The data are like the following:
ID date
1 4/12/2008
1 4/13/2008
1 5/11/2008
2 3/21/2009
2 4/22/2009
2 8/05/2009
...
the date column are in the format "%m/%d/%y". i wish to obtain
ID month
1 4
1 4
1 5
2 15
2 16
2 20
...
also, for the same ID with two identical month, I only want to keep the
last one. can any expert help with this question?
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