Rank Function
Because y[1] and y[5] are not the same in Part1 but are in Part2:
# using y from Part1 y[5] - y[1]
[1] 1.110223e-16 You could round your numbers to 2 digits, say:
rank(round(100*y)) # y is from Part1
[1] 3.5 5.0 1.0 2.0 3.5
On 10/10/06, Li Zhang <zhanglitt at yahoo.com> wrote:
Does anyone know why the two rank functions gives different results? I need to use the rank function in a "for" loop, so the sequence to be ranked is given values in the form of part (1). How can I use assignment like in part (1) to get correct ranks as in part (2)? Thank You Part (1) i<-1.94 b<-0.95-i c<-1.73-i d<-2.62-i y<-c(0.68,0.95,b,c,d) y 0.68 0.95 -0.99 -0.21 0.68 rank(y) 3 5 1 2 4 Part(2) rank(c(0.68,0.95,-0.99,-0.21,0.68)) 3.5 5.0 1.0 2.0 3.5
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