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Power Law Exponents

Have you looked at coef(lm (log10(vouty) ~ log10(voutx)))?  This the 
slope / coefficient of log10(voutx) should be an estimate of the power.

	  Why do yo think the exponent is wrong?  If the plot looks like a 
rough ellipse, then this is a standard way to fit this.

	  This assumes that log10(vouty)=b0+b1*log10(voutx)+e,
where the e's are indepndent, normally distributed with mean 0 and 
constant variance.  The reverse, log10(voutx)=c0+c1*log10(vouty)+f, is a 
different model:  The first assumes there is no error in voutx;  all the 
error is in vouty.  The second assumes the opposite.

	  If neither is what you want, then you need some kind of errors in X 
regression.  I need that so seldom that I'm not certain what softwarre 
to suggest, but I believe I've seen comments on this list indicating 
there is R software available for solving this problem.

hth, spencer graves
Martin H. Robinson wrote: