Defining partial list of variables

If your column names have no spaces the following should work

?x<-strsplit(gsub("[\n ]","",
?"hhsize,urban,male,
+ gov,nongov,married"),","); x

On Tue, Jan 5, 2021 at 11:47 AM Steven Yen <styen at ntu.edu.tw 
<mailto:styen at ntu.edu.tw>> wrote:

    Here we go! BUT, it works great for a continuous line. With line
    break(s), I got the nuisance "\n" inserted.

    > x<-strsplit("hhsize,urban,male,gov,nongov,married",","); x

    [[1]]
    [1] "hhsize"? "urban"?? "male"??? "gov"???? "nongov" "married"

    > x<-strsplit("hhsize,urban,male,

    +???????????? gov,nongov,married",","); x
    [[1]]
    [1] "hhsize"??????????? "urban" "male"????????????? "\n???????????
    gov"
    [5] "nongov"??????????? "married"

    On 2021/1/5 ?? 05:34, Eric Berger wrote:

    zx<-strsplit("age,exercise,income,white,black,hispanic,base,somcol,grad,employed,unable,homeowner,married,divorced,widowed",",")



    On Tue, Jan 5, 2021 at 11:01 AM Steven Yen <styen at ntu.edu.tw
    <mailto:styen at ntu.edu.tw>> wrote:

        Thank you, Jeff. IMO, we are all here to make R work better
        to suit our
        various needs. All I am asking is an easier way to define
        variable list
        zx, differently from the way z0 , x0, and treat are defined.

        ?> zx<-colnames(subset(mydata,select=c(
        +
        age,exercise,income,white,black,hispanic,base,somcol,grad,employed,
        +???? unable,homeowner,married,divorced,widowed)))
        ?> z0<-c("fruit","highblood")
        ?> x0<-c("vgood","poor")
        ?> treat<-"depression"
        ?> eq1 <-my.formula(y="depression",x=zx,z0)
        ?> eq2 <-my.formula(y="bmi",?????? x=zx,x0)
        ?> eq2t<-my.formula(y="bmi",?????? x=zx,treat)
        ?> eqs<-list(eq1,eq2); eqs
        [[1]]
        depression ~ age + exercise + income + white + black + hispanic +
        ???? base + somcol + grad + employed + unable + homeowner +
        married +
        ???? divorced + widowed + fruit + highblood

        [[2]]
        bmi ~ age + exercise + income + white + black + hispanic + base +
        ???? somcol + grad + employed + unable + homeowner + married +
        ???? divorced + widowed + vgood + poor

        ?> eqt<-list(eq1,eq2t); eqt
        [[1]]
        depression ~ age + exercise + income + white + black + hispanic +
        ???? base + somcol + grad + employed + unable + homeowner +
        married +
        ???? divorced + widowed + fruit + highblood

        [[2]]
        bmi ~ age + exercise + income + white + black + hispanic + base +
        ???? somcol + grad + employed + unable + homeowner + married +
        ???? divorced + widowed + depression

        On 2021/1/5 ?? 04:18, Jeff Newmiller wrote:

        > IMO if you want to hardcode a formula then simply hardcode

        a formula. If you want 20 formulas, write 20 formulas. Is
        that really so bad?

        >
        > If you want to have an abbreviated way to specify sets of

        variables without conforming to R syntax then put them into
        data files and read them in using a format of your choice.

        >
        > But using NSE to avoid using quotes for entering what

        amounts to in-script data is abuse of the language justified
        by laziness... the amount of work you put yourself and anyone
        else who reads your code through is excessive relative to the
        benefit gained.

        >
        > NSE has its strengths... but as a method of creating data

        objects it sucks. Note that even the tidyverse (now) requires
        you to use quotes when you are not directly referring to
        something that already exists. And if you were... you might
        as well be creating a formula.

        >
        > On January 4, 2021 11:14:54 PM PST, Steven Yen

        <styen at ntu.edu.tw <mailto:styen at ntu.edu.tw>> wrote:

        >> I constantly define variable lists from a data frame

        (e.g., to define a

        >>
        >> regression equation). Line 3 below does just that. Placing

        each

        >> variable
        >> name in quotation marks is too much work especially for a

        long list so

        >> I
        >> do that with line 4. Is there an easier way to accomplish

        this----to

        >> define a list of variable names containing "a","c","e"?

        Thank you!

        >>

        >>> data<-as.data.frame(matrix(1:30,nrow=6))
        >>> colnames(data)<-c("a","b","c","d","e"); data

        >>? ? a? b? c? d? e
        >> 1 1? 7 13 19 25
        >> 2 2? 8 14 20 26
        >> 3 3? 9 15 21 27
        >> 4 4 10 16 22 28
        >> 5 5 11 17 23 29
        >> 6 6 12 18 24 30

        >>> x1<-c("a","c","e"); x1 # line 3

        >> [1] "a" "c" "e"

        >>> x2<-colnames(subset(data,select=c(a,c,e))); x2 # line 4

        >> [1] "a" "c" "e"
        >>
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        reproducible code.