repeating values in an index two by two
Or you can use the integer divide and remainder operators:
> n <- 30
> x <- seq(0, len=n)
> + (x %% 2) + (x %/% 4)*2 + 1 # period 2 oscillator + jump by 2 every fourth
[1] 1 2 1 2 3 4 3 4 5 6 5 6 7 8 7
[16] 8 9 10 9 10 11 12 11 12 13 14 13 14 15 16
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-----Original Message----- From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Iakub Henschen Sent: Monday, November 11, 2013 8:42 AM To: r-help at r-project.org Subject: Re: [R] repeating values in an index two by two
n<-7 rep(seq(1,n,2), each=4)+c(0,1,0,1)
[1] 1 2 1 2 3 4 3 4 5 6 5 6 7 8 7 8 rep(), seq(), rbind(), apply() ... whatever: internally there will always be iteration via some loop :-) Ia. On Mon, Nov 11, 2013 at 11:16 AM, Carl Witthoft <carl at witthoft.com> wrote:
Here's a rather extreme solution: foo<-rep(1:6,each=2) Rgames> foo [1] 1 1 2 2 3 3 4 4 5 5 6 6 Rgames> foo[rep(c(1,3,2,4),3)+rep(c(0,4,8),each=4)] [1] 1 2 1 2 3 4 3 4 5 6 5 6 In the general case, then, it would be something like foo<- rep(1:N, each = 2) # foo is of length(2*N) foo[rep(c(1,3,2,4),2*N/4 + rep( seq(0, 3*N/4,by=4),each=4)] Note that the refolding requires the sequence to have length a multiple of 4. Patrick Burns wrote
f1
function(x) {
one <- matrix(1:x, nrow=2)
as.vector(rbind(one, one))
}
<environment: 0x000000000daaf1c0>
> f1(8)
[1] 1 2 1 2 3 4 3 4 5 6 5 6 7 8 7 8 Pat On 11/11/2013 12:11, Federico Calboli wrote:
Hi All, I am trying to create an index that returns something like 1,2,1,2,3,4,3,4,5,6,5,6,7,8,7,8 and so on and so forth until a predetermined value (which is obviously even). I am trying very hard to avoid for loops or for loops front
ends.
I'd be obliged if anybody could offer a suggestion. BW F
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-- Patrick Burns
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twitter: @burnsstat @portfolioprobe http://www.portfolioprobe.com/blog http://www.burns-stat.com (home of: 'Impatient R' 'The R Inferno' 'Tao Te Programming')
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