How to put factor variables in an nls formula ?
On 8/18/05, FranÂçois Morneau <francois.morneau at cirad.fr> wrote:
Hello,
I want to fit a Gompertz model for tree diameter growth that depends on a 4
levels edaphic factor ('Drain') and I don't manage to introduce the factor
variable in the formula.
Dinc is the annual diameter increment and D is the Diameter.
>treestab > Dinc D Drain
[1,] 0.03 26.10 2 [2,] 0.04 13.05 1 [3,] 0.00 24.83 1 [4,] 0.00 15.92 4 [5,] 0.00 12.25 4 [6,] 0.00 11.78 4 [7,] 0.00 16.87 4 [8,] 0.00 15.12 4 [9,] -0.01 13.53 4 [10,] 0.04 16.55 3 [11,] 0.025 16.07 3 [12,] 0.00 30.24 3 [13,] 0.06 15.28 2 etc…
>contrasts(Drain)<-contr.sum(4) >mymodel<-nls(Dinc~r*(1+Drain)*D*log(Asym/D), data=treestab, start(r=0.05,
Asym=40))
Error in numericDeriv(form[[3]], names(ind), env) :
Missing value or an infinity produced when evaluating the model
In addition: Warning messages:
1: + not meaningful for factors in: Ops.factor(1, Drain)
2: + not meaningful for factors in: Ops.factor(1, Drain)
It is not clear to me what you are trying to do. Can you give us a bit more information such as how many parameter estimates you expect to obtain and what they would represent?
Do I need to use another function instead of nls to correctly include the factor 'Drain' ? Thanks, FranÂçois
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