Binning the data based on a value
Just a clarification: I can't get round to work as I first expected so if you want to do bins by 100's you'd probably want: split(a, cut(a$spending, breaks = (0:5)*100)) Michael On Mon, Dec 5, 2011 at 3:41 PM, R. Michael Weylandt
<michael.weylandt at gmail.com> wrote:
I'd so something like split(a, a$spending) and you can include a round(a$spending, -2) or something similar if you want to group by the 100's. Michael On Mon, Dec 5, 2011 at 3:37 PM, Diviya Smith <diviya.smith at gmail.com> wrote:
Hello there, I have a matrix with some data and I want to split this matrix based on the values in one column. Is there a quick way of doing this? I have looked at cut but I am not sure how to exactly use it? for example: I would like to split the matrix "a" based on the spending such that the data is binned groups [0..99],[100..199]...and so on. a <- data.frame(patient=1:7, charges=c(100,500,200,90,400,500,600), ?age=c(0,3,5,7,10,16,19), ?spending=c(10, 60, 110, 200, 250, 400, 450)) Expected ?output - bin[1] <- c(10, 60) bin[2] <- c(110, 200, 250) bin[3] <- c(400, 450) NOTE that the number of data points in each bin is not the same and the empty bins are removed (since there are no points between [199..299], bin[3] starts at 400. Any help would be most appreciated. Thank you in advance. Diviya ? ? ? ?[[alternative HTML version deleted]]
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