Efficient way to Calculate the squared distances for a set ofvectors to a fixed vector
Hi Wei Wu, What about: x <- matrix(rnorm(20000*5),ncol=5) y <- rnorm(5) distances <- rowSums((x-y)**2) Cheers, Tsjerk On Wed, Aug 24, 2011 at 8:43 AM, Enrico Schumann
<enricoschumann at yahoo.de> wrote:
You could do something like this: # data nrows <- 20000L ncols <- 5L myVec <- array(rnorm(nrows * ncols), dim = c(nrows, ncols)) y <- rnorm(ncols) temp <- t(myVec) - y result <- colSums(temp * temp) # check all.equal(as.numeric(crossprod(myVec[1L, ] - y)), result[1L]) #... (And don't use a data.frame, but a matrix.) regards, Enrico
-----Urspr?ngliche Nachricht----- Von: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] Im Auftrag von Wei Wu Gesendet: Mittwoch, 24. August 2011 07:18 An: r-help at r-project.org Betreff: [R] Efficient way to Calculate the squared distances for a set ofvectors to a fixed vector I am pretty new to R. So this may be an easy question for most of you. I would like to calculate the squared distances of a large set (let's say 20000) of vectors (let's say dimension of 5) to a fixed vector. Say I have a data frame MY_VECTORS with 20000 rows and 5 columns, and one 5x1 vector y. I would like to efficiently calculate the squared distances?between each of the 20000 vectors in MY_VECTORS and y. The squared distance between two vectors x and y can be calculated: distance <- crossprod(x-y) Without looping, what is?the efficient code to achieve this? Thanks.
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______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Tsjerk A. Wassenaar, Ph.D. post-doctoral researcher Molecular Dynamics Group * Groningen Institute for Biomolecular Research and Biotechnology * Zernike Institute for Advanced Materials University of Groningen The Netherlands