(no subject)

Excellent job providing example data and a desired result.

This code works on the example you provided.  Hope it helps.

Jean

# reshape the info data frame
library(tidyr)
info2 <- gather(myinfo, set, val, -game)
info2$set <- as.numeric(gsub("[[:alpha:]]", "", info2$set))

# add a new column to the x data frame
y <- t(x[,grep("char", names(x))])
newx <- x
newx$char <- row(y)[y==1]

# merge and define winner
res <- merge(newx, info2)
res$winner <- with(res, ifelse(char==val, 1, 0))
res


On Wed, Dec 23, 2015 at 3:35 PM, Dimitri Liakhovitski
<dimitri.liakhovitski at gmail.com> wrote:

Merry upcoming Christmas - for those of us who celebrate it!

# I have data frame x.
x <- data.frame(game = c(rep(1, 4), rep(2, 4)), set = rep(c(1,1,2,2),
2), player = rep(1:2, 4),
                char1 = c(1,0,0,0,0,0,0,1), char2 =
c(0,0,1,0,0,1,0,0), char3 = c(0,1,0,1,0,0,0,0),
                char4 = c(0,0,0,0,1,0,1,0))
x
# There are several games (2 here). Each game has several sets (2
here. In each set participate
# several players (2 here).
# Each player possesses 1 or 4 possible characteristics.
# For example, in game 1, set 1, player 1 has characteristic 1 and player
2 -
# characteristic 3

# I also have data frame myinfo:
(myinfo <- data.frame(game = 1:2, set1 = c(3, 4), set2 = c(2, 1)))
# It tells me:
# in game 1, set 1 the winner was the player with characteristic 3
# in game 1, set 2 the winner was the player with characteristic 2, etc.

# I need to merge the 2 to produce the result below.
# I just need an additional column that - for each game and each set -
# has a 1 in the row of the player who had the winning characteristic
# (as per myinfo) and has a 0 otherwise.

result <- x
result$winner <- c(0, 1, 1, 0, 1, 0, 0, 1)
result

# I have written a long loop that loops through each set of each game,
identifies
# which characteristic wins in myinfo, and puts a 1 against the winning
row.
# But it's taking forever. Could it be done faster? Thanks a lot!

# Important: In my real game the number of players could be more than
2 and so can
# the number of games and the number of sets per game.
# However, we can assume that the number of sets per game is always the
same,
# and the number of players per set is always the same.


--
Dimitri Liakhovitski