a more elegant approach to getting the majority level
you could try this: x <- factor(sample(letters[1:3], 20, TRUE)) ####### tab <- table(x) names(tab)[tab == max(tab)] I hope it helps. Best, Dimitris ---- Dimitris Rizopoulos Ph.D. Student Biostatistical Centre School of Public Health Catholic University of Leuven Address: Kapucijnenvoer 35, Leuven, Belgium Tel: +32/16/336899 Fax: +32/16/337015 Web: http://www.med.kuleuven.ac.be/biostat/ http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm ----- Original Message ----- From: "Rajarshi Guha" <rxg218 at psu.edu> To: "R" <r-help at stat.math.ethz.ch> Sent: Thursday, May 26, 2005 4:36 PM Subject: [R] a more elegant approach to getting the majority level
Hi, I have a factor and I would like to find the most frequent level. I think my current approach is a bit long winded and I was wondering if there was a more elegant way to do it: x <- factor(sample(1:0, 5,replace=TRUE)) levels(x)[ which( as.logical((table(x) == max(table(x)))) == TRUE ) ] (The length of x will always be an odd number, so I wont get a tie in max()) Thanks, ------------------------------------------------------------------- Rajarshi Guha <rxg218 at psu.edu> <http://jijo.cjb.net> GPG Fingerprint: 0CCA 8EE2 2EEB 25E2 AB04 06F7 1BB9 E634 9B87 56EE ------------------------------------------------------------------- Alcohol, an alternative to your self - 'Alcohol' by the Bare Naked Ladies
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