How to use strings from a data.frame as the argument of an expression() for plot
Try this: e <- expression(O[3], NO, NO[2]) opar <- par(mfrow = c(2,2)) for(i in 1:3) plot(1, 1, type = "b", main = bquote(.(e[[i]]) ~ Year ~ 2005)) par(opar) Also please read the last line to every post to r-help and particularly note the part about reproducible examples. x and y.were undefined.
On 12/20/06, MrJ Man <auxsvr at yahoo.com> wrote:
Greetings,
I would like to use a data.frame with strings to feed
the expression() in the title of a plot. The way I did
this is:
molecules
<-data.frame(name=c("o3","no","no2"),expression=c("quote(O[3])","quote(NO)","quote(NO[2])"))
for (mol in c(5,7,9)) {
plot(x, y, type="b",
main=eval(substitute(expression(paste(mol," Year
2005")),
list(mol=eval(parse("",text=toString(molecules$expression[(mol-3)/2])))))))
}
However, this looks cumbersome and I'm sure there is a
way to do this in R that is much more simple. The
complexity of the expression above is mainly due to
the fact that the only way I could find to convert a
string read from a data.frame into a symbol was to
enclose it in "quote(symbol)" and call toString on the
result, since selecting string data from a data.frame
returns an object that is not a string (why is this
so? A data.frame with doubles returns doubles).
What do you think?
Thanks in advance.
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