if then in R versus SAS

-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org]
On Behalf Of Marc Schwartz
Sent: Friday, August 24, 2012 12:06 PM
To: ramoss
Cc: r-help at r-project.org
Subject: Re: [R] if then in R versus SAS

On Aug 24, 2012, at 1:03 PM, ramoss <ramine.mossadegh at finra.org> wrote:

I am new to R and I have the following SAS statements:

if otype='M' and ocond='1' and entry='a.Prop' then MOC=1;
else MOC=0;

How would I translate that into R code?

Thanks in advance

See ?ifelse and ?Logic, both of which are covered in "An Introduction to
R" (http://cran.r-project.org/manuals.html).

 MOC <- ifelse((otype == 'M') & (ocond == '1') & (entry == 'a.Prop'), 1,
0)

You might also want to think about getting a copy of:

R for SAS and SPSS Users
Robert Muenchen
http://www.amazon.com/SAS-SPSS-Users-Statistics-Computing/dp/0387094172

Regards,

Marc Schwartz

I would second Mark's recommendation to carefully work through "An Introduction to R" and to get Robert Muenchen's book.  If the variables otype, ocond, and entry are scalar values, then the translation from SAS to R is very straight-forward:

if(otype=='M' && ocond=='1' && entry=='a.Prop') MOC <- 1 else MOC <- 0
It's almost certain that they are not scalar though, so Marc's idea is likely right. 

Just let me add that ifelse() is not actually needed:

MOC <- as.numeric((otype == 'M') & (ocond == '1') & (entry == 'a.Prop'))

will do. (And the as.numeric bit is only to convert FALSE/TRUE to 0/1)

Hope this is helpful,

Dan

Daniel Nordlund
Bothell, WA USA

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if then in R versus SAS

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