Fortune? [was: Re: quotation marks and scan]
On Sun, 17 Nov 2013, Ted Harding wrote:
[See in-line below] On 17-Nov-2013 22:38:30 Rolf Turner wrote:
(1) The backslashes are not really there; they are an artefact of the R
print() function.
Try cat(u,"\n"). I think this might be an FAQ.
(2) Is not your problem the fact that your are setting "replacement"
equal to the
thing you are trying to get rid of? I.e. don't you want
v <- gsub(pattern='\"',replacement='',x=u) ???
Either I am misunderstanding your intent or you need another cup of coffee.
Is the above line a Fortune?
Why not? ;-) On R-Forge now. Z
cheers,
Rolf
On 11/18/13 11:07, Erin Hodgess wrote:
Dear R People:
I'm sure that this is a very simple problem, but I have been wresting with
it for some time.
I have the following file that has the following one line:
CRS("+init=epsg:28992")
Fair enough. I scan it into R and get the following:
u
[1] "CRS(\"+init=epsg:28992\")"
gsub(pattern='\"',replacement='"',x=u)
[1] "CRS(\"+init=epsg:28992\")" I need to get rid of the extra quotation marks and slashes. I've tried all sorts of things, including gsub, as you see, but no good.
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------------------------------------------------- E-Mail: (Ted Harding) <Ted.Harding at wlandres.net> Date: 17-Nov-2013 Time: 23:55:48 This message was sent by XFMail
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.