lm with an arbitrary number of terms
You need to paste() together a formula. There's an example in ?formula.
Try,
n <- 10
rhs <- paste("x", 1:n, collapse = "+", sep = "")
lhs <- "y ~"
f <- as.formula(paste(lhs, rhs))
Then pass `f' into lm().
-roger
_______________________________
UCLA Department of Statistics
rpeng at stat.ucla.edu
http://www.stat.ucla.edu/~rpeng
On Wed, 2 Apr 2003, Richard Nixon wrote:
Hello folks,
Any ideas how to do this?
data.frame is a data frame with column names "x1",...,"xn"
y is a response variable of length dim(data.frame)[1]
I want to write a function
function(y, data.frame){
lm(y~x1+...+xn)
}
This would be easy if n was always the same.
If n is arbitrary how could I feed the x1+...+xn terms into lm(response~terms)?
Thanks
Richard
--
Dr. Richard Nixon
MRC Biostatistics Unit, Cambridge, UK
http://www.mrc-bsu.cam.ac.uk/personal/richard
Tel: +44 (0)1223 330382, Fax: +44 (0)1223 33038
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