Always via logical expressions. In this case you can use the logical
expression
myDF$b != "0"
to give you a vector of TRUE/FALSE
B.
On Sep 25, 2017, at 8:00 AM, Shane Carey <careyshan at gmail.com> wrote:
This is super, really helpfull. Sorry, one final question, lets say I
wanted to remove 0's rather than NAs , what would it be?
Thanks
On Mon, Sep 25, 2017 at 12:41 PM, Boris Steipe <boris.steipe at utoronto.ca>
myDF <- data.frame(a = c("<0.1", NA, 0.3, 5, "Nil"),
b = c("<0.1", 1, 0.3, 5, "Nil"),
stringsAsFactors = FALSE)
# you can subset the b-column in several ways
myDF[ , 2]
myDF[ , "b"]
myDF$b
# using the column, you make a logical vector
! is.na(as.numeric(myDF$b))
# This can be used to select the rows you want
myDF[! is.na(as.numeric(myDF$b)), ]
B.
On Sep 25, 2017, at 7:30 AM, Shane Carey <careyshan at gmail.com> wrote:
Hi,
Lets say this was a dataframe where I had two columns
a <- c("<0.1", NA, 0.3, 5, "Nil")
b <- c("<0.1", 1, 0.3, 5, "Nil")
And I just want to remove the rows from the dataframe where there were
NAs in the b column, what is the syntax for doing that?
Thanks in advance
On Fri, Sep 22, 2017 at 5:04 PM, Shane Carey <careyshan at gmail.com>
Super,
Thanks
On Fri, Sep 22, 2017 at 4:57 PM, Boris Steipe <
boris.steipe at utoronto.ca> wrote:
a <- c("<0.1", NA, 0.3, 5, "Nil")
a
[1] "<0.1" NA "0.3" "5" "Nil"
Warning message:
NAs introduced by coercion
On Sep 22, 2017, at 11:48 AM, Shane Carey <careyshan at gmail.com>
Hi,
How do I extract just numbers from the following list:
a=c("<0.1",NA,0.3,5,Nil)
so I want to obtain: 0.3 and 5 from the above list
Thanks
--
Le gach dea ghui,
*Shane Carey*
*GIS and Data Solutions Consultant*
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