help with grep list files

Hello,

Maybe if you change the pattern to

"^lld[A-Z0-9]*\\.dat$"

Hope this helps,

Rui Barradas

Em 20-02-2017 21:41, Glenn Schultz escreveu:
All,

I have the following files in a directory and I would like only a list of those starting with ?lld" and ending with ?dat?.  I used the following and it gives me the lld files

  list.files(path = readpath, pattern = "^lld[A-Z0-9]")

to get just .dat files I tried

  list.files(path = readpath, pattern = "^lld[A-Z0-9].dat$?) but nothing is returned

below is a dput from the first command.  $ is an end of line anchor correct?  What am I doing wrong?

Best,
Glenn

c("lld022017_AB7755_AS0038.dat", "lld022017_AS0039_AS5210.dat",
"lld022017_AS5211_AS7917.dat", "lld022017_AS7918_AT8661.dat",
"lld022017_AT8662_AW6667.dat", "lld022017_AW6668_AZ3066.dat",
"lld022017_AZ3067_BC9534.dat", "lld022017_BC9535_MA2230.dat",
"lld022017_MA2231_MB0288.dat", "lld022017.zip")

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help with grep list files

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