Just a note:
If the dataset is not ordered, this could result in:
?set.seed(24)
?xNew<-x[sample(1:nrow(x),6,replace=FALSE),]
idxN<-which(c(TRUE,diff(as.integer(xNew[,2]))!=0))
?xNew[-idxN,]
#[1] "2/1/13" "18"???? "30"?
xNew1<-xNew[order(xNew[,2],xNew[,1]),]
idx<-which(c(TRUE,diff(as.integer(xNew1[,2]))!=0))
?xNew1[-idx,]
#???? [,1]???? [,2] [,3]
#[1,] "1/5/13" "15" "25"
#[2,] "1/9/13" "15" "28"
#[3,] "2/5/13" "18" "35"
#[4,] "2/9/13" "18" "38"
#Same problem applies to my solution
? xNew2<- as.data.frame(xNew, stringsAsFactors=FALSE)
?xNew[with(xNew2,ave(as.numeric(as.Date(V1,"%m/%d/%y")),V2,FUN=function(x) !x%in% min(x)))!=0,] #keeps the original order of xNew
#???? [,1]???? [,2] [,3]
#[1,] "1/5/13" "15" "25"
#[2,] "2/9/13" "18" "38"
#[3,] "1/9/13" "15" "28"
#[4,] "2/5/13" "18" "35"
A.K.
----- Original Message -----
From: Rui Barradas <ruipbarradas at sapo.pt>
To: Andras Farkas <motyocska at yahoo.com>
Cc: "r-help at r-project.org" <r-help at r-project.org>
Sent: Tuesday, July 30, 2013 9:08 AM
Subject: Re: [R] selection based on dates
Hello,
Try the following.
idx <- which(c(TRUE, diff(as.integer(x[,2])) != 0))
x[-idx,]
Also, note that in constructs such as
a <-c("1/1/13",15,20)
both 15 and 20 are coerced to character. So your matrix is a matrix of
chars. For different types of data, use data.frames
Hope this helps,
Rui Barradas
Em 30-07-2013 13:13, Andras Farkas escreveu:
Dear All
please provide your insigths on the following:
I have:
a <-c("1/1/13",15,20)
b <-c("1/5/13",15,25)
c <-c("1/9/13",15,28)
d <-c("2/1/13",18,30)
e <-c("2/5/13",18,35)
f <-c("2/9/13",18,38)
x <-matrix(c(a,b,c,d,e,f),ncol=3,byrow=TRUE)
What I would like to do is to eliminate certain rows of this matrix based on the date column values. As you can see, in the second column my values (15 and 18) repeat 3 times each, so this column serves as an ID number if you will. Thus each ID numbers show up with 3 different date values in the first column. Now I would like to eliminate the rows with the earliest date per ID number. My result should look like this:
z <-x[-c(1,4),]
as allways, your help is greatly appreciated,
thanks,
Andras