if() command
Hi Sorry, I am not sure why sometimes is a text from my answeres stripped off.
On 14 Sep 2005 at 14:09, Carlos Mauricio Cardeal Mende wrote:
Ok Petr, I run your suggestion and I got this message:
> age<-sample(seq(10,50,10), 20, replace=T)
>
> if (age <=10) {group <- 1} else if (age > 10 & age <= 20)
{group <-
2} else {group <- 3}
Warning message:
the condition has length > 1 and only the first element will be
used
in: if (age <= 10) {
What does it means ?
Others has already answered it but I told you that if command is not vhat you probably want and suggested to use cut e.g. cutvector <- c(0,10,20,100) group <- as.numeric(cut(age,cutvector)) You can change your cutvector according to your wish anytime before calling the second function HTH Petr
And when I look to the database I have no new classification ! Could you help please ? Mauricio Petr Pikal escreveu:
Hallo On 13 Sep 2005 at 10:29, Carlos Maur??cio Cardeal Mende
wrote:
Hi everyone ! Could you please help me with this problem ? I??ve trying to write a code that assign to a variable the
content
from another, but all I??ve got is a message error. For
example:
if (age <=10) {group == 1}
else if (age > 10 & age <= 20) {group == 2}
else {group == 3}
if you put your statement on one line it works (at least it does
not
give you syntax error) but the result is hardly what you really
expect
age<-sample(seq(10,50,10), 20, replace=T)
if (age <=10) {group <- 1} else if (age > 10 & age <= 20)
{group <-
2} else {group <- 3} if (age <=10) {group == 1} else if (age >
10 &
age <= 20) {group == 2} else {group == 3}
Maybe you want something like
group<-as.numeric(cut(age,c(0,10,20,100)))
but it is only guess
HTH
Petr
Syntax error
Or
if (age <=10) {group == 1}
else (age > 10 & age <= 20) {group == 2}
else {group == 3}
Syntax error
I know that is possible to find the solution by ifelse command
or
even recode command, but I??d like to use this way, because I
can
add another variable as a new condition and I believe to
expand the
possibilites. Thanks, Mauricio
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