Message-ID: <48BC00DC.3060809@yahoo.de>
Date: 2008-09-01T14:49:00Z
From: Antje
Subject: another histogram question
In-Reply-To: <da79af330809010710p30a3295eh31d42f05966c6b54@mail.gmail.com>
Henrique Dallazuanna schrieb:
> You can do this:
>
> hh <- lapply(h, head, mh)
> hh$breaks <- head(h$breaks, mh + 1)
> class(hh) <- "histogram"
> plot(hh)
Thanks a lot, that's exactly what I need :-) (I did not consider the class...)
Putting an xlim could also be an solution but I think this is much more clean :-)
Ciao,
Antje
>
> On Mon, Sep 1, 2008 at 10:44 AM, Antje <niederlein-rstat at yahoo.de
> <mailto:niederlein-rstat at yahoo.de>> wrote:
>
> Hi there,
>
> I hope this question is not as stupid as the one before ...
> I tried to shorten my histogram (because the distribution is quite
> skewed and I simply don't want to see the long tail but still use
> the histogram plot). How can I do something like this? (The example
> does not work but I don't know why...)
>
> data <- rnorm(100) # as example, of course this is not skewed...
>
> h <- hist(data, plot=FALSE)
> mh <- 5
> hh <- list(h$breaks[0:(mh+1)],
> h$counts[0:mh],h$intensities[0:mh],h$density[0:mh],h$mids[0:mh],h$xname,h$equidist)
> names(hh) <- names(h)
> plot(hh)
>
>
> Antje
>
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>
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paran?-Brasil
> 25? 25' 40" S 49? 16' 22" O