accessing the attributes of a list inside lapply()
Hi, What about: > as.list(names(l)) [[1]] [1] "a" [[2]] [1] "b" [[3]] [1] "c" HTH, Eric
At 15:59 19/11/2004, Adrian Alexa wrote:
Hello R-users, I have the following problem, that I want to solve efficiently: I have a named list, for example:
l <- list(a = 1, b = 3, c = 'asd') l
$a [1] 1 $b [1] 3 $c [1] "asd" I know that I can iterate through it using lapply() function, but I would also like to able to get the list names or some attributes of l in the lapply(). For example if I use names() function in the call of lapply() I get:
lapply(l, names)
$a NULL $b NULL $c NULL My question is if I can get something like:
lapply(l, get_attr)
$a [1] a $b [1] b $c [1] c I can do this very easy with a for() loop but my list is quite big and I would like to get a decent running time. I don't need only the attributes of the list(I can obtain them by using attributes() or attr() function), but for my list the names of the elements are given me information that I need. Also I must mention that the elements of the list can by of any type. Any solution is welcome. Many thanks, Adrian -- Adrian Alexa Max-Planck-Institut fuer Informatik Stuhlsatzenhausweg 85 Room 514 66123 Saarbruecken, Germany
______________________________________________ R-help at stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html