Handling dates
On Fri, Aug 19, 2005 at 01:35:45PM +0200, Peter Dalgaard wrote:
G??ran Brostr??m <gb at stat.umu.se> writes:
I have a problem with some functions handling dates, in packages 'date' and
'survival' (they seem to be identical). For instance, from the documentation,
--------------------
mdy.date {survival}
R Documentation
Convert to Julian Dates
Description
Given a month, day, and year, returns the number of days since January 1, 1960.
Usage
mdy.date(month, day, year, nineteen = TRUE, fillday = FALSE,
fillmonth = FALSE)
----------------------------
but
library(survival) mdy.date(12, 1, 1977)
[1] 1Dec77 Similar strange results appear in other date-related functions. I plan to write functions that converts, eg, "1977-01-31" to the real number 1977.084 and back. What function in R does what 'mdy.date' claims to do?
mdy.date does ...
dput(mdy.date(12, 1, 1977))
structure(6544, class = "date")
Thanks, I should have remembered that what functions print and what they return can be quite different things. This one returns "Julian dates". Which can be seen under "Value". But isn't the Description a bit misleading?
mdy.date(1, 31, 1977)/365.2425+1960 # or /365.25 if you really want 1977.084
[1] 1977.085
What I want is that the the fraction (0.084) should be equal to the fraction of the full year 1977 that is spent between 1977-01-01, at 00:00:00 and 1977-01-31, at noon. I know how to do it now. Thanks again, G??ran
But with recent R's, as.Date is a better bet:
c(as.Date("1977-01-31") - as.Date("0000-01-01"))/365.2425
[1] 1977.084 (notice that you need the c() to avoid the nonsense of
(as.Date("1977-01-31") - as.Date("0000-01-01"))/365.2425
Time difference of 1977.084 days ) -- O__ ---- Peter Dalgaard ??ster Farimagsgade 5, Entr.B c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~~~~~~~~~ - (p.dalgaard at biostat.ku.dk) FAX: (+45) 35327907