find and replace string
try this:
x <- c('sta_+1+0_field2ndtry_0000$01.cfg'
+ , 'sta_+1+0_field2ndtry_0000$01.cfg' + , 'sta_+1-0_field2ndtry_0000$01.cfg' + , 'sta_+1+0_field2ndtry_0000$01.cfg' + )
# find matching fields
values <- grep("[^+]*\\+[^+]*\\+0", x, value = TRUE)
# split into two pieces
splitValues <- sub("([^+]*\\+[^+]*\\+)0(.*)", "\\1^\\2", values)
for (i in splitValues){
+ for (j in 0:3){
+ print(sub("\\^", j, i))
+ }
+ }
[1] "sta_+1+0_field2ndtry_0000$01.cfg"
[1] "sta_+1+1_field2ndtry_0000$01.cfg"
[1] "sta_+1+2_field2ndtry_0000$01.cfg"
[1] "sta_+1+3_field2ndtry_0000$01.cfg"
[1] "sta_+1+0_field2ndtry_0000$01.cfg"
[1] "sta_+1+1_field2ndtry_0000$01.cfg"
[1] "sta_+1+2_field2ndtry_0000$01.cfg"
[1] "sta_+1+3_field2ndtry_0000$01.cfg"
[1] "sta_+1+0_field2ndtry_0000$01.cfg"
[1] "sta_+1+1_field2ndtry_0000$01.cfg"
[1] "sta_+1+2_field2ndtry_0000$01.cfg"
[1] "sta_+1+3_field2ndtry_0000$01.cfg"
On Fri, Dec 2, 2011 at 6:30 AM, Alaios <alaios at yahoo.com> wrote:
Dear all, I would like to search in a string for the second occurrence of a symbol and replace the symbol after it For example my strings look like sta_+1+0_field2ndtry_0000$01.cfg I want to find the digit that comes after the second +, in that case is zero and then over a loop create the strings below sta_+1+0_field2ndtry_0000$01.cfg sta_+1+1_field2ndtry_0000$01.cfg sta_+1+2_field2ndtry_0000$01.cfg sta_+1+3_field2ndtry_0000$01.cfg and so on.. I have already tried strsplit but this will make things more complex... Could you please help me with that? B.R Alex ? ? ? ?[[alternative HTML version deleted]]
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