list to data frame by rows ...

I am not yet shutting up on this :)

Thanks for the suggestions ... problem is that the code was
given as an illustration, in reality do4split would do
some complicated magic calculations that yield several
interesting results of mixed type.

[...]

cl <- 1:2
names(cl) <- c("a","b")
as.data.frame(lapply(cl,function(i)sapply(result,"[[",i)))

  a b
x x 2
y y 4

The problem here is that the functionality gets pulled out of 
do4split which isnt really possible in the *real* situation.

[...]
If you'd like another approach, I kind of think I'd be inclined to do
what you do in your do4split function in separate pieces, each one
acting on one or more of the columns.  I assume you want more rows
than columns.  The number of functions would be at most the number of
parts you do in your do4split function, and then it's already in the
form you require, so it's probably no longer to code, and maybe
quicker to run.

As mentioned above, its not possible to split up do4split into
several pieces without doing the same calculations over and over
again.

So I guess there is no way around doing it iteratively. I would have
thought that adding the rows iteratively to an empty data frame
would be the obvious approach, but I am unable to make an empty 
data frame:
data.frame(list(a=c(),b=c()))
Error in names<-.default(*tmp*, value = vnames) : 
        names attribute must be the same length as the vector

However, its possible to make an list with "0 rows":
ltmp<-list(a=c(),b=c())

for (s in splitted) {
  print(s)
  tmp <- do4split(s)
  for (i in 1:length(tmp)) {
    ltmp[[i]]<-c(ltmp[[i]],tmp[[i]])
  }  
}

I would be curious how efficient this is and what actually happens.
Will ltmp[[i]]<-c(ltmp[[i]],tmp[[i]]) just extend the column or
will the whole content be copied every time? 

The final step 
  as.data.frame(ltmp)
again has the problem that the character columns will be converted
to levels. But when a column has class AsIs it wont:
  data.frame(lapply(ltmp,I))

Johann
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