order() and na.last
"Richards, Tom" wrote:
Hello:
I'm not sure what is going on in these two statements. the first
seems to be right, but the second is a problem:
order(c(3,2,4,NA),na.last=TRUE)
[1] 2 1 3 4
order(c(3,2,4,NA),na.last=FALSE)
Error in .NotYetUsed("na.last != TRUE") : argument `na.last != TRUE' is not
used (yet)
order(c(3,2,4,NA))
I am using R 1.2.2 under Windows NT. Thanks.
Let's read the help (?order):
na.last: for controlling the treatment of `NA's. If `TRUE', missing
values in the data are put last; if `FALSE', they are put
first; if `NA', they are removed. Currently, `TRUE' is the
only possible value.
To point it out: "Currently, 'TRUE' is the only possible value.
Uwe Ligges
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