chron problem: extracting days and years
as.POSIXlt is nothing to do with chron. You are confusing two systems. months() is part of base R: days() is not, and it does not say it works with R's dates. The answer is on the help page for months(), BTW:
c(testdate$mday, testdate$year)
[1] 17 98 or look at ?strftime for e.g.
format(testdate, "%Y")
[1] "1998"
format(testdate, "%d")
[1] "17" if you want a character string.
On Sun, 3 Feb 2002, John Field wrote:
Hello r-help, I'm trying to split a character vector of dates of the form "dd-mmm-yy" into component days, months and years. But
> library(chron)
> testdate<-as.POSIXlt(strptime("17-Sep-98","%d-%b-%y"))
> testdate
[1] "1998-09-17"
> months(testdate)
[1] "September" # which is fine, but for days and years I get
> days(testdate)
NULL
> years(testdate)
NULL
>
According to "?days" these should work. What am I doing wrong? Is there an easier way to achieve what I want? (I'm running R1.3.0 under Win98).
An R upgrade is long overdue ....
Brian D. Ripley, ripley at stats.ox.ac.uk Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272860 (secr) Oxford OX1 3TG, UK Fax: +44 1865 272595 -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._