problem with ifelse
Since your code has things like this:
z<-numeric(length(t ((
either you have a serious problem with your email client or you need
to reread some introductory material and take a hard look at your
code.
Also note that g() doesn't work, because it contains the statement
return(m) but m is undefined within g().
Meanwhile, you could provide what I asked: a statement of what you
expect your code to produce given particular input. Otherwise how
would we know if we've offered the right solution, since your function
doesn't work? Using set.seed() would be a useful component of this
reproducible example.
Without having a working if poorly-written function to go by or a
clear results statement, I'm not interested in trying to rewrite your
code. But some thoughts:
Here's a new version of f().
f2 <- function(c1, c2) {
r <- pmax(c1 + c2, c1 + 0.5)
cbind(c1, r)
}
It looks like you expected f() to be able to take vectors, but in g()
you only return one value. Is that a mistake, or what you wanted?
Since you're also using cbind(), I assume it's a mistake.
Again, there are lots of problems here that suggest that you are
coming from some other programming language and have not taken the
time to learn much about R's syntax. This is easily remedied by
reading the introduction.
Sarah
On Wed, May 30, 2012 at 3:32 PM, Christopher Kelvin
<chris_kelvin2001 at yahoo.com> wrote:
Hello Sarah,
Thank you for your response. Below is the complete code. My desire is to obtain interval censored data through simulation to fit it on the weibull distribution to estimate the parameters. I am actually not very sure of the code correctness. You may try it and advice me on what to do and also about it correctness if time will permit you.
Thank you
g<-function(c1,c2) {
? f<-function(c1,c2) {
? ? u<-c1
? ? h<-c1+c2
? ? k<-c1+0.5
? ? r<-numeric (length(c1))
? ? for(i in 1:length(r)) r[i]<-max(h[i],k[i])
? ? return( cbind (u,r))}
? r1<-f(c1,c2)
? r2<-f(r1[2],r1[1])
? r3<-f(r2[2],r2[1])
? r4<-f(r3[2],r3[1])
? r5<-f(r4[2],r4[1])
? a<-(cbind(r1[1],r2[1],r3[1],r4[1],r5[1],r5[2]))
? return(m )}
c1<-runif(1,0,1.5)
c2<-runif(1,0,0.5)
m<-g(c1,c2)
tdata<-rweibull(25,0.8,1.5)
v<-c(0,m,999)
y<-function(t,v){
? z<-numeric(length(t ((
? ? s<-numeric(length(t ((
? ? ? for(i in 1:length(t)){
? ? ? ? for(j in 1:length(v-1))
? ? ? ? { ifelse ((t[i]>v[j] & t< v[j+1] ),{z[i]<-v[j];s[i]<-v[j+1]},NA)}}
? ? ? return(cbind(z,s))}
y(t,v)
Chris Kelvin
Hi,
The error with ifelse() seems to be that you have no idea what ifelse() does.
As far as I can tell, you tried to construct code that does something like this:
y<-function(tdata,v){
? ?z <- rep(NA, length(tdata))
? ?s <- z
? ?for(i in 1:length(tdata)) {
? ? ? for(j in 1:length(v-1)) {
??? ??? ??? if(tdata[i] > v[j] & tdata[i] < v[j+1]) {
??? ??? ??? ??? z[i]<-v[j]
??? ??? ??? ??? s[i]<-v[j+1]
??? ??? ??? }
??? ??? }
??? }
? ?return(cbind(z,s))
}
But what's with all the (( instead of ))?
And are you certain that the logic in the if statement is correct?
If you tell us what you expect the results to be for given input
values, we can help with that part too. Including making this more
Rish: the nested for-loop construct is entirely unnecessary here, but
I'm disinclined to rewrite it unless I actually know what you're
trying to achieve.
Incidentally, your example is only nearly-reproducible, since we don't
know what m is.
Sarah
On Wed, May 30, 2012 at 10:01 AM, Christopher Kelvin
<chris_kelvin2001 at yahoo.com> wrote:
Dear all,
?The code below is used to generate interval censored data but unfortunately there is an error with the ifelse which i am not able to rectify.
?Can somebody help correct it for me.
Thank you
t<-rexp(20,0.2)
v<-c(0,m,999)
y<-function(t,v){
? z<-numeric(length(t ((
? ? s<-numeric(length(t ((
? ? ? for(i in 1:length(t)){
? ? ? ? for(j in 1:length(v-1))
? ? ? ? { ifelse ((t[i]>v[j] & t< v[j+1] ),{z[i]<-v[j];s[i]<-v[j+1]},NA)}}
? ? ? return(cbind(z,s))}
y(t,v)
Sarah Goslee http://www.functionaldiversity.org