Help in R code

Hi

Keep your reply to the list.

Hm. There is natural language processing section in Task View. Maybe you could use already developed instruments for processing text. I vaguely remember there was also some article in R journal about text mining.

And searching internet by

R text mining

gave me plenty of possible suggestions including e.g package tm.

First line of your code gave me an error

s <- unlist(lapply(posText, function(x) { str_split(x, "\n") }))

Error in lapply(posText, function(x) { : object 'posText' not found

And again
you still fail to keep to the recommended way of asking questions

1.       Plain text, not HTML posts

2.       input and output data sent as result of dput(posText[selection])

3.       provide ***reproducible*** code
Instead of trying to persuade all of us to accept your way of mailing you shall comply to ours if you want any reasonable help.

Cheers
Petr



Petr Pikal

From: deepak aggarwal [mailto:talk4deepak at gmail.com]
Sent: Thursday, March 03, 2016 2:07 PM
To: PIKAL Petr
Subject: Re: [R] Help in R code


           I have a column A having sentences and column B have some words. I want to check the part of speech column B word belongs to sentence present in column A.
Currently I am able to get part of speech for a single sentence using following code:
I am trying to get part of speech corresponds to each sentence in text file. Please suggest code for this.

Hi

AFAIK what you say now is quite different from what you have told before. You want to get rid of all sentences which lack vattrwords.

Maybe it can be done by charmatch

test<-paste("AAA AAA", "BBB", "CCC CCC", sep=".")
test

[1] "AAA AAA.BBB.CCC CCC"

test2<-c("AAA", "CCC")
test.s<-unlist(strsplit(test, "\\.<file:///\\.>"))
test.s[charmatch(test2, test.s)]

[1] "AAA AAA" "CCC CCC"

BTW, you still fail to keep to the recommended way of asking questions
Plain text, not HTML posts
input and output data sent as result of dput()
provide reproducible code with errors you encountered.

Cheers
Petr



From: deepak aggarwal [mailto:talk4deepak at gmail.com<mailto:talk4deepak at gmail.com>]
Sent: Wednesday, March 02, 2016 8:59 AM
To: PIKAL Petr
Cc: r-help at r-project.org<mailto:r-help at r-project.org>

Subject: Re: [R] Help in R code

Hi Petr,
#loading word to be matched
at_list <- read.delim(file='C:/******/All.txt', header=FALSE, stringsAsFactors=FALSE)
names(at_list) <- c('attr')
at_list$attr <- tolower(at_list$attr)

vattribute<-at_list$attr

#loading sentences to be checked
posText <- read.delim(file='C:/*****/Sentenc.txt', header=FALSE, stringsAsFactors=FALSE)
posText <- unlist(lapply(posText, function(x) { str_split(x, "\n") }))

test<-vattribute

test1 <- unlist(strsplit(posText,split="\\.<file:///\\.>"))
# test1 <- strsplit(posText,".",fixed=TRUE)[[1]]
#test2<- test1[match(test1,test)]
test2<-test1[grep(paste(test, collapse="|"),test1)]

score <- c(test,test2)


#add row
newrow <- c(test1, score)
final_scores <- rbind(newrow)
final_scores
result<-as.data.frame(final_scores)

write.table(result, "C:/******/otput.txt", sep="\t")

Well, so again, my first answer was maybe too elaborated.

0. Send your replies also to help list.
1. Do not post in HTML.
2. Send some data by using output from
dput(yourobject)
3. Prepare desired output and again show it by dput(yourresult)
I still do not understand your desired output. In first sequence you dropped words ?He is? and ?he?, in second ?word? and ?can be?

Did you check?
4. Check if

?strsplit together with ?"%in%" can be of some help.

test <- "he is smart and fast in his work"

test

[1] "he is smart and fast in his work"

unlist(strsplit(test, " "))

[1] "he"    "is"    "smart" "and"   "fast"  "in"    "his"   "work"

unlist(strsplit(test, " ")) %in% "smart"
[1] FALSE FALSE  TRUE FALSE FALSE FALSE FALSE FALSE
If the above does not work for you, you need to evaluate regular expressions.

See e.g.
?gsub

Cheers
Petr

From: deepak aggarwal [mailto:talk4deepak at gmail.com<mailto:talk4deepak at gmail.com>]
Sent: Tuesday, March 01, 2016 5:06 PM
To: PIKAL Petr
Subject: Re: [R] Help in R code


Sentence

Words

word string

1

he is a nice human being.he has great talent of singing

human,talent

a nice human being .,has great talent of singing

2

Word is having environmental issues which can be solved at local level nw

environmental,local

is having environmental issues which,solved at local level nw


sentence column has 1000 sentences and words have some selected words already written
now i want r code using which i can get word string in such a way that first human is searched in sentence 1 and then 2 words before human and 2 words after human will be writen in word string next it will search word talent and add it to word string

so in nutsheel for every word in words column it will fetch 2 words before and 2 words after where match is found.

Seeking your help on this.

Regards
Deepak

Hi

See in line

-----Original Message-----
From: R-help [mailto:r-help-bounces at r-project.org<mailto:r-help-bounces at r-project.org>] On Behalf Of deepak
aggarwal
Sent: Tuesday, March 01, 2016 1:30 PM
To: r-help at r-project.org<mailto:r-help at r-project.org>
Subject: [R] Help in R code

Hi ,

Seeking your help in coding following requirement in R.

Vector 1 has sentences for ex. vector 1="he is a nice human being","he
is smart and fast in his work"

vector 2 has keywords found in each sentence seperated by comma for
ex. vector2 for vector 1 =nice,being vector 2 for vector 1 =smart,work

I want output to be vector 3 which will show 2 words before and after
where match is found

vector 1                                       vector2        vector 3
he is a nice human being              nice,being        is a nice
human,human being
he is smart and fast in his work   smart,work        he is smart,in his
work

in all i want vector 3 to how 2 words before and aftr to each word of
vector 2 from vector 1.

really appriciate your quick help on this.

OK. Some very quick help:

1. Do not post in HTML, your mail is barely readable.
2. Send some data by using output from
dput(yourobject)
3. Instead of vaguely explaining what you want to do, prepare desired output and again show it by dput(yourresult)
4. Check if

?strsplit together with ?"%in%" can be of some help.

test <- "he is smart and fast in his work"

test

[1] "he is smart and fast in his work"

unlist(strsplit(test, " "))

[1] "he"    "is"    "smart" "and"   "fast"  "in"    "his"   "work"

unlist(strsplit(test, " ")) %in% "smart"
[1] FALSE FALSE  TRUE FALSE FALSE FALSE FALSE FALSE

Cheers
Petr

Thanks & Regards
Deepak

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