inserting one backslash
RH Koning wrote:
Hello, I am not very familiar with regular expressions and escaping. I
need to replace the %-signs in a character vector with elements as
"income 0%-33%# to be replaced by "income 0\%-33\%" (for later use in
LaTeX). Using
gsub("%","\\%","income 0%-33%")
does not give the desired result. However, gsub("%","\\\\%","income
0%-33%") gives "income 0\\%-33\\%", one backslash too much. What is the
appropriate expression to get the desired output (one backslash before
each %-sign)?
Actually, you got the answer. See the difference between:
> gsub("%","\\\\%","income 0%-33%")
[1] "income 0\\%-33\\%"
> cat(gsub("%","\\\\%","income 0%-33%"))
income 0\%-33\%
HTH,
--sundar