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random numbers with constraints

Am Wed, 27 Jan 2021 09:03:15 +0100
schrieb Denis Francisci <denis.francisci at gmail.com>:
In principle it should be possible. But I guess you are asking too much
with three given values considering that you only have one paramter for
the exponential distribution. For instance, if you only had given min
and max, and wanted a normal distribution then you could have just taken
410 random values from a standard normal: x=rnorm(410) then centered it:
x=x-mean(x) then scaled it so its span equals the one for your given max
(M) and min (m) values: x=x*(M-m)/(max(x)-min(x)) and finally shift it
such that the mininum becomes m: x=x-min(x)+m. Note however, that the
things you are allowed to do with your vector of random numbers depend
on the distribution if you want the result to still follow that type of
distribution.