Sent from my phone. Please excuse my brevity.
On April 7, 2016 4:57:04 AM PDT, Michael Artz <michaeleartz at gmail.com> wrote:
>Thaks so much! And how would you incorporate lapply() here?
>
>On Thu, Apr 7, 2016 at 6:52 AM, David Barron <dnbarron at gmail.com>
>wrote:
>
>> ifelse is vectorised, so just use that without the loop.
>>
>> colordata$response <- ifelse(colordata$color == 'blue', 1, 0)
>>
>> David
>>
>> On 7 April 2016 at 12:41, Michael Artz <michaeleartz at gmail.com>
>wrote:
>>
>>> Hi I'm not sure how to ask this, but its a very easy question to
>answer
>>> for
>>> an R person.
>>>
>>> What is an easy way to check for a column value and then assigne a
>new
>>> column a value based on that old column value?
>>>
>>> For example, Im doing
>>> colordata <- data.frame(id = c(1,2,3,4,5), color = c("blue", "red",
>>> "green", "blue", "orange"))
>>> for (i in 1:nrow(colordata)){
>>> colordata$response[i] <- ifelse(colordata[i,"color"] == "blue",
>1, 0)
>>> }
>>>
>>> which works, but I don't want to use the for loop I want to
>"vecotrize"
>>> this. How would this be implemented?
>>>
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>>>
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>>> PLEASE do read the posting guide
>>> http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>>
>>
>>
>
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>
>______________________________________________
>R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide
>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
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