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Assessing the name of an object within an argument

Yes, I was too fast there, sorry. I sent a correction right after but must have picked Reply instead of Replay All.

Cheers
Thomas
On 10 January 2017 at 10:31:30, Bert Gunter (bgunter.4567 at gmail.com<mailto:bgunter.4567 at gmail.com>) wrote:
This is false. formals() gives the FORMAL argument list of the function, not the ACTUAL arguments supplied. That is obtained by the construction

deparse(substitute(dataset))

The OP should consult a good R tutorial for this and other uses of substitute(), part of the "computing on the language" functionality of R.

Bert
On Jan 10, 2017 4:04 AM, "Thomas Mailund" <mailund at birc.au.dk<mailto:mailund at birc.au.dk>> wrote:
You can get that using `formals()`.

my_func <- function(dataset = iris)
{
  #print(dataset) # here I do not want to print the dataset but the name
  # of the object - iris in this case - instead

  print(formals()$dataset) # this is what you want
}

This gives you what the arguments were as an alist. It won?t always be a name, of course, but when it is, as in this case, that will be a symbol you can print.

Cheers
        Thomas
On 10 January 2017 at 09:51:55, g.maubach at weinwolf.de<mailto:g.maubach at weinwolf.de> (g.maubach at weinwolf.de<mailto:g.maubach at weinwolf.de>(mailto:g.maubach at weinwolf.de<mailto:g.maubach at weinwolf.de>)) wrote:

            
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