Best way to test for numeric digits?
?s 15:59 de 18/10/2023, Leonard Mada via R-help escreveu:
Dear List members,
What is the best way to test for numeric digits?
suppressWarnings(as.double(c("Li", "Na", "K",? "2", "Rb", "Ca", "3")))
# [1] NA NA NA? 2 NA NA? 3
The above requires the use of the suppressWarnings function. Are there
any better ways?
I was working to extract chemical elements from a formula, something
like this:
split.symbol.character = function(x, rm.digits = TRUE) {
?? ?# Perl is partly broken in R 4.3, but this works:
?? ?regex = "(?<=[A-Z])(?![a-z]|$)|(?<=.)(?=[A-Z])|(?<=[a-z])(?=[^a-z])";
?? ?# stringi::stri_split(x, regex = regex);
?? ?s = strsplit(x, regex, perl = TRUE);
?? ?if(rm.digits) {
?? ???? s = lapply(s, function(s) {
?? ???? ??? isNotD = is.na(suppressWarnings(as.numeric(s)));
?? ???? ??? s = s[isNotD];
?? ???? });
?? ?}
?? ?return(s);
}
split.symbol.character(c("CCl3F", "Li4Al4H16", "CCl2CO2AlPO4SiO4Cl"))
Sincerely,
Leonard
Note:
# works:
regex = "(?<=[A-Z])(?![a-z]|$)|(?<=.)(?=[A-Z])|(?<=[a-z])(?=[^a-z])";
strsplit(c("CCl3F", "Li4Al4H16", "CCl2CO2AlPO4SiO4Cl"), regex, perl = T)
# broken in R 4.3.1
# only slightly "erroneous" with stringi::stri_split
regex = "(?<=[A-Z])(?![a-z]|$)|(?=[A-Z])|(?<=[a-z])(?=[^a-z])";
strsplit(c("CCl3F", "Li4Al4H16", "CCl2CO2AlPO4SiO4Cl"), regex, perl = T)
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Hello,
If you want to extract chemical elements symbols, the following might work.
It uses the periodic table in GitHub package chemr and a package stringr
function.
devtools::install_github("paleolimbot/chemr")
split_chem_elements <- function(x) {
data(pt, package = "chemr", envir = environment())
el <- pt$symbol[order(nchar(pt$symbol), decreasing = TRUE)]
pat <- paste(el, collapse = "|")
stringr::str_extract_all(x, pat)
}
mol <- c("CCl3F", "Li4Al4H16", "CCl2CO2AlPO4SiO4Cl")
split_chem_elements(mol)
#> [[1]]
#> [1] "C" "Cl" "F"
#>
#> [[2]]
#> [1] "Li" "Al" "H"
#>
#> [[3]]
#> [1] "C" "Cl" "C" "O" "Al" "P" "O" "Si" "O" "Cl"
It is also possible to rewrite the function without calls to non base
packages but that will take some more work.
Hope this helps,
Rui Barradas
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