identifying weeks (dates) that certain days (dates) fall into
Sorry for renewing the topoic. I thought it worked but now I've run
into a little problem:
# My data frame with dates for week starts (Mondays)
y<-data.frame(week=seq(as.Date("2009-12-28"),
as.Date("2011-12-26"),by="week") )
# I have a vector of super bowl dates (including the future one for 2012):
sbwl.dates<-as.Date(c("2005-02-06","2006-02-05","2007-02-04","2008-02-03","2009-02-01","2010-02-07","2011-02-06","2012-02-05"))
I want to find the weeks in y that contain super bowl dates for
applicable years. I am trying:
sbwl.weeks<-findInterval(sbwl.dates, y$week)
sbwl.weeks<-sbwl.weeks[sbwl.weeks>0]
(sbwl.weeks)
6 58 105
y$flag<-0 y$flag[sbwl.weeks]<-1 6 and 58 are correct. But why am I getting 105 (the last row)? Any way to fix it? Thanks a lot! Dimitri On Tue, Aug 2, 2011 at 12:57 PM, Dimitri Liakhovitski
<dimitri.liakhovitski at gmail.com> wrote:
Thanks a lot, everyone! Dimitri On Tue, Aug 2, 2011 at 12:34 PM, Dennis Murphy <djmuser at gmail.com> wrote:
Hi: You could try the lubridate package: library(lubridate) week(weekly$week) week(july4) [1] 27 27
week
function (x) yday(x)%/%7 + 1 <environment: namespace:lubridate> which is essentially Gabor's code :) HTH, Dennis On Tue, Aug 2, 2011 at 7:36 AM, Dimitri Liakhovitski <dimitri.liakhovitski at gmail.com> wrote:
Hello!
I have dates for the beginning of each week, e.g.:
weekly<-data.frame(week=seq(as.Date("2010-04-01"),
as.Date("2011-12-26"),by="week"))
week ?# each week starts on a Monday
I also have a vector of dates I am interested in, e.g.:
july4<-as.Date(c("2010-07-04","2011-07-04"))
I would like to flag the weeks in my weekly$week that contain those 2
individual dates.
I can only think of a very clumsy way of doing it:
myrows<-c(which(weekly$week==weekly$week[weekly$week>july4[1]][1]-7),
? ? ? ?which(weekly$week==weekly$week[weekly$week>july4[2]][1]-7))
weekly$flag<-0
weekly$flag[myrows]<-1
It's clumsy - because actually, my vector of dates of interest (july4
above) is much longer.
Is there maybe a more elegant way of doing it?
Thank you!
--
Dimitri Liakhovitski
marketfusionanalytics.com
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-- Dimitri Liakhovitski marketfusionanalytics.com
Dimitri Liakhovitski marketfusionanalytics.com